The memory allocated for a struct is equal to the sum of the memory of its individual members, considering _______.
- padding
- initialization
- inheritance
- encapsulation
Memory alignment requirements can cause "padding" between members of a struct, which can increase the total memory size of the struct. This is essential for data to be accessed in an optimized manner on the hardware.
What is the purpose of the throw keyword in exception handling in C++?
- to propagate
- to hide
- to prevent
- to execute
In C++ exception handling, the throw keyword is used to signal the occurrence of an exception. When an error condition arises, using the throw keyword can help propagate the exception up the call stack until it's caught by an appropriate catch block.
How does the continue statement affect the execution of a nested loop structure?
- It jumps to the next iteration of the innermost loop.
- It jumps to the next iteration of the outermost loop.
- It stops the entire program execution.
- It restarts all loops from the beginning.
The continue statement causes the current iteration of the loop to terminate, and the control jumps to the next iteration of the innermost loop that contains the continue. It won't affect any outer loops in the nested structure unless it's placed in the outer loop itself.
What will happen if the break statement is used outside any loop or switch statement?
- The program will crash.
- It will skip the next statement.
- It results in a compilation error.
- It breaks out of the main function.
Using the break statement outside of a loop or switch will result in a compilation error. The break statement is meant to terminate the nearest enclosing loop or switch where it appears. If it's placed elsewhere, it won't make logical sense to the compiler.
The _______ keyword is used to specify a class should not be instantiated directly, but only used as a base class.
- virtual
- abstract
- sealed
- interface
In C++, an "abstract" class is one that cannot be instantiated directly. It is intended to be used as a base class from which other classes are derived, and it may have one or more pure virtual functions.
A function in your codebase is exhibiting unexpected behavior because it is being passed an argument of an incorrect type, but the compiler is not generating an error. What might be a potential reason for this, and how could it be resolved?
- The compiler is outdated.
- Function overloading is causing ambiguity.
- Argument type has an implicit conversion to the expected type.
- There's an error in the compiler settings.
Implicit type conversions in C++ can sometimes lead to unexpected behavior, especially if a function argument undergoes an unintended conversion. This can be resolved by either making the type conversion explicit or by using strong type checks and avoiding implicit conversions.
The keyword _______ is used to specify that a function should be compiled inline.
- auto
- static
- inline
- register
The "inline" keyword suggests to the compiler that it should attempt to embed the function's code in the place where the function is called, avoiding a function call.
You are working on a large-scale simulation software where numerous animal species are modeled. Which type of inheritance might be most suitable to model individual animal species without encountering the diamond problem?
- Single Inheritance
- Multiple Inheritance
- Hierarchical Inheritance
- Multilevel Inheritance
Single inheritance ensures that a class inherits from only one other class, thus avoiding the diamond problem. The diamond problem arises in languages that support multiple inheritance and can result in ambiguity in the inheritance hierarchy. Single inheritance ensures a clear, linear progression without any ambiguities.
What is the primary reason for using smart pointers over raw pointers in modern C++?
- To increase execution speed
- To use less memory
- To look modern
- To manage memory automatically
Smart pointers, such as unique_ptr, shared_ptr, and weak_ptr, were introduced in C++ to provide automated memory management. They automatically handle the destruction of objects they point to, thereby preventing common issues like memory leaks and dangling pointers.
What is the role of the return statement in a lambda function?
- To indicate the end of the lambda function.
- To return a value from the lambda to the calling function.
- It determines the type of the lambda.
- It can't be used in lambda functions.
Lambda functions, like regular functions, can return values. If the lambda's body contains more than one statement, a return statement can be used to specify which value is returned. If the lambda's body consists of a single return statement, the return type is automatically inferred by the compiler.