How does the virtual base class resolve the diamond problem in C++? 

  • By preventing multiple copies 
  • By duplicating base class 
  • By altering access specifiers 
  • By overloading functions
The diamond problem arises in C++ multiple inheritance when one class inherits from two classes that have a common base class. This can lead to ambiguity regarding which base class member should be accessed. The "virtual" keyword before the base class prevents the compiler from creating multiple instances of the base class, thus resolving the diamond problem.

What is the primary reason behind certain languages optimizing tail recursion? 

  • To improve memory efficiency 
  • To make code look cleaner 
  • To speed up compilation time 
  • To allow deeper recursion depth
Tail recursion optimization, often referred to as Tail Call Optimization (TCO), primarily serves to improve memory efficiency. When a recursive call is the last thing a function does (tail recursion), some languages can optimize it to reuse the current function's stack frame for the next function call. This can lead to significant savings in stack space, especially for deep recursive calls. It allows recursion-intensive algorithms to run without consuming as much memory or leading to a stack overflow.

Which operator is used to access the memory address of a variable in C++? 

  • * (Asterisk) 
  • & (Ampersand) 
  • % (Percent) 
  • + (Plus)
The "&" (ampersand) operator is used to get the memory address of a variable in C++. For instance, if int x = 10;, then &x will give the memory address where the integer x is stored. The asterisk (*), on the other hand, is used for dereferencing.

Which of the following statements about the struct and class keywords is true? 

  • Only structs can have member functions 
  • Structs are always public, and classes are always private 
  • Both can have member functions, but default access is different 
  • Classes support inheritance, structs don't
Both struct and class in C++ can have member functions, data members, and can support inheritance. The primary difference is the default access level: members of a struct are public by default, whereas members of a class are private. Other functionalities between them are essentially identical.

To remove all instances of a particular value from a C++ STL vector, you should use the _______ algorithm. 

  • find 
  • sort 
  • erase 
  • remove
While erase can remove elements from a vector, to efficiently remove all instances of a value, you'd first use remove to move those elements to the end and then use erase. This is known as the "erase-remove" idiom in C++.

The keyword _______ is used to access the base class’s members in the derived class. 

  • super 
  • this 
  • parent 
  • base
In C++, the "base" keyword is not actually used. The correct way to access base class members is through the use of the base class name or the scope resolution operator. However, "base" is a term from C#.

The concept of encapsulation involves bundling the data () and the methods () that operate on the data into a single unit. 

  • objects, functions 
  • variables, operators 
  • members, methods 
  • attributes, functions
Encapsulation is a key concept in object-oriented programming where the data (members) and the functions (methods) that operate on this data are bundled together as a single unit known as a class.

Which of the following is a correct statement about friend functions in C++? 

  • They are member functions of a class 
  • They can be inherited by derived classes 
  • They always improve performance of the program 
  • They do not have access to the 'this' pointer of the class
In C++, the 'this' pointer is an implicit pointer to the object on which a member function is called. Since friend functions are not member functions of a class, they do not have access to this pointer. They operate as external functions with special access permissions.

In a C++ application, you have a stream of data being logged... 

  • Write to a temporary file first 
  • Use std::ofstream::flush after every write 
  • Use file locking mechanisms 
  • Implement journaling or write-ahead logging
Implementing journaling or write-ahead logging means changes are first logged to a separate, sequential log. In case of failures, this log can be used to bring the file back to a consistent state. This provides a safeguard against data corruption or loss during unforeseen events.

You are designing a complex numerical algorithm with multiple cooperating classes that need to share internal data for efficiency. How might the friend keyword be used effectively in this context? 

  • Use the friend keyword for all member functions. 
  • Limit the use of friend to only those classes/functions that strictly require access. 
  • Use the friend keyword with external utility functions only. 
  • Declare all classes as friends of each other.
The friend keyword should be used judiciously. By limiting its use only to those classes or functions that genuinely need access, you maintain a degree of encapsulation and make the design intent clear, ensuring that only necessary components have deeper access.