How does the virtual base class resolve the diamond problem in C++? 

  • By preventing multiple copies 
  • By duplicating base class 
  • By altering access specifiers 
  • By overloading functions
The diamond problem arises in C++ multiple inheritance when one class inherits from two classes that have a common base class. This can lead to ambiguity regarding which base class member should be accessed. The "virtual" keyword before the base class prevents the compiler from creating multiple instances of the base class, thus resolving the diamond problem.

What does the struct keyword allow a C++ programmer to do? 

  • Execute a set of statements repeatedly 
  • Connect to databases 
  • Create a group of variables under one name 
  • Create a virtual function
The struct keyword in C++ allows a programmer to define a composite data type that groups variables of different data types under a single name. This makes it easier to organize related data. Initially in C, struct was used to define a simple group, but in C++ it's similar to a class.

In what situation might explicit template specialization be used in C++? 

  • When all versions of the template should behave the same. 
  • When a specific version of a template requires different behavior. 
  • When templates are used with multiple inheritance. 
  • When we need to add more template parameters.
Explicit template specialization allows for defining a different implementation of a template for a specific type or set of types. This is particularly useful when a general template definition would be correct for most types but not for a specific type or set of types. For instance, if most types can be handled with a general algorithm, but one type requires a more optimized or different approach, explicit specialization can be used for that type.

Using continue in a while loop will skip to the _______. 

  • end of the loop 
  • beginning of the loop 
  • next iteration 
  • previous iteration
The continue statement, when encountered in a loop (like a while loop), will skip any subsequent statements in the current iteration and jump to the beginning of the next iteration.

What is the primary reason behind certain languages optimizing tail recursion? 

  • To improve memory efficiency 
  • To make code look cleaner 
  • To speed up compilation time 
  • To allow deeper recursion depth
Tail recursion optimization, often referred to as Tail Call Optimization (TCO), primarily serves to improve memory efficiency. When a recursive call is the last thing a function does (tail recursion), some languages can optimize it to reuse the current function's stack frame for the next function call. This can lead to significant savings in stack space, especially for deep recursive calls. It allows recursion-intensive algorithms to run without consuming as much memory or leading to a stack overflow.

Which operator is used to access the memory address of a variable in C++? 

  • * (Asterisk) 
  • & (Ampersand) 
  • % (Percent) 
  • + (Plus)
The "&" (ampersand) operator is used to get the memory address of a variable in C++. For instance, if int x = 10;, then &x will give the memory address where the integer x is stored. The asterisk (*), on the other hand, is used for dereferencing.

Which of the following statements about the struct and class keywords is true? 

  • Only structs can have member functions 
  • Structs are always public, and classes are always private 
  • Both can have member functions, but default access is different 
  • Classes support inheritance, structs don't
Both struct and class in C++ can have member functions, data members, and can support inheritance. The primary difference is the default access level: members of a struct are public by default, whereas members of a class are private. Other functionalities between them are essentially identical.

To remove all instances of a particular value from a C++ STL vector, you should use the _______ algorithm. 

  • find 
  • sort 
  • erase 
  • remove
While erase can remove elements from a vector, to efficiently remove all instances of a value, you'd first use remove to move those elements to the end and then use erase. This is known as the "erase-remove" idiom in C++.

The keyword _______ is used to access the base class’s members in the derived class. 

  • super 
  • this 
  • parent 
  • base
In C++, the "base" keyword is not actually used. The correct way to access base class members is through the use of the base class name or the scope resolution operator. However, "base" is a term from C#.

The concept of encapsulation involves bundling the data () and the methods () that operate on the data into a single unit. 

  • objects, functions 
  • variables, operators 
  • members, methods 
  • attributes, functions
Encapsulation is a key concept in object-oriented programming where the data (members) and the functions (methods) that operate on this data are bundled together as a single unit known as a class.