How does the logical AND (&&) operator behave when the first operand is false?
- It checks the second operand.
- It returns false immediately.
- It returns true immediately.
- It throws an exception.
In C++, the logical AND (&&) operator is "short-circuiting". This means if the first operand is false, it won't even check the second operand because the overall result will definitely be false. This behavior can be used for efficient coding practices.
Imagine you are maintaining a C++ application where memory leaks are a constant issue. Which type of pointer would be the best to use to ensure that dynamically allocated objects are properly deallocated?
- auto_ptr
- shared_ptr
- weak_ptr
- unique_ptr
unique_ptr is a smart pointer that retains sole ownership of an object. It ensures that there's only one unique_ptr pointing to the object, and it automatically deallocates the object once the unique_ptr goes out of scope.
C++ was initially called _______ during its early development phase.
- C with Classes
- C#
- C*
- C--
C++ was originally called "C with Classes" before it was named C++. The name reflects the language's evolution as an extension of the C programming language.
How does the compiler handle inline function calls?
- By replacing the function call with its body.
- By linking the function at runtime.
- By creating a virtual table for the function.
- By allocating dynamic memory for the function.
Inline functions are meant to optimize function calls by eliminating the overhead of a call and return sequence. When the compiler inlines a function, it replaces the function call with the actual body of the function, integrating it directly into the calling code, which can improve performance.
The keyword _______ is used to specify that a function should be compiled inline.
- auto
- static
- inline
- register
The "inline" keyword suggests to the compiler that it should attempt to embed the function's code in the place where the function is called, avoiding a function call.
A function in your codebase is exhibiting unexpected behavior because it is being passed an argument of an incorrect type, but the compiler is not generating an error. What might be a potential reason for this, and how could it be resolved?
- The compiler is outdated.
- Function overloading is causing ambiguity.
- Argument type has an implicit conversion to the expected type.
- There's an error in the compiler settings.
Implicit type conversions in C++ can sometimes lead to unexpected behavior, especially if a function argument undergoes an unintended conversion. This can be resolved by either making the type conversion explicit or by using strong type checks and avoiding implicit conversions.
The _______ keyword is used to specify a class should not be instantiated directly, but only used as a base class.
- virtual
- abstract
- sealed
- interface
In C++, an "abstract" class is one that cannot be instantiated directly. It is intended to be used as a base class from which other classes are derived, and it may have one or more pure virtual functions.
What will happen if the break statement is used outside any loop or switch statement?
- The program will crash.
- It will skip the next statement.
- It results in a compilation error.
- It breaks out of the main function.
Using the break statement outside of a loop or switch will result in a compilation error. The break statement is meant to terminate the nearest enclosing loop or switch where it appears. If it's placed elsewhere, it won't make logical sense to the compiler.
How does the continue statement affect the execution of a nested loop structure?
- It jumps to the next iteration of the innermost loop.
- It jumps to the next iteration of the outermost loop.
- It stops the entire program execution.
- It restarts all loops from the beginning.
The continue statement causes the current iteration of the loop to terminate, and the control jumps to the next iteration of the innermost loop that contains the continue. It won't affect any outer loops in the nested structure unless it's placed in the outer loop itself.
What is the purpose of the throw keyword in exception handling in C++?
- to propagate
- to hide
- to prevent
- to execute
In C++ exception handling, the throw keyword is used to signal the occurrence of an exception. When an error condition arises, using the throw keyword can help propagate the exception up the call stack until it's caught by an appropriate catch block.
The memory allocated for a struct is equal to the sum of the memory of its individual members, considering _______.
- padding
- initialization
- inheritance
- encapsulation
Memory alignment requirements can cause "padding" between members of a struct, which can increase the total memory size of the struct. This is essential for data to be accessed in an optimized manner on the hardware.
If you want to force floating-point division in C++ when dividing two integers, one of the numbers should be _______.
- casted as float
- multiplied by zero
- negated
- subtracted by one
In C++, to force floating-point division when dividing two integers, you can cast one or both of the integers to a floating-point type (like float or double). By doing this, the division will result in a floating-point value, preserving any fractional part. For instance, (float)5 / 2 would result in 2.5 instead of 2.