How does pass by reference in C++ handle underlying memory allocation?
- Creates a new copy of the object
- Uses dynamic memory allocation
- Allocates memory on the heap
- Doesn't allocate additional memory
When passing by reference in C++, no additional memory is allocated. Instead, a reference serves as an alias to the original variable. It simply refers to the memory location of the original variable and doesn't create a separate copy of it. This contrasts with pass by value, where a copy of the object is made, which might lead to additional memory consumption.
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