How can a function indicate that it will not throw any exceptions?
- By using the noexcept specifier
- By returning a null pointer
- By using the try block without catch
- By marking it as static
The noexcept specifier in C++11 and later indicates that a function does not throw exceptions. If such a function does throw an exception, the program will terminate (usually by calling std::terminate). This can be a useful optimization hint for the compiler.
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