How does C++ handle situations when both declaration and definition of a function are available but with different default argument values?
- It results in a compilation error
- The compiler generates a warning
- The compiler selects the default values from the declaration
- The compiler selects the default values from the definition
In C++, when both declaration and definition of a function are available but with different default argument values, the compiler selects the default values from the definition. This ensures consistency in behavior when the function is called from different parts of the code, as the definition takes precedence.
Loading...
Related Quiz
- Unlike if-else, switch-case in C++ does not support _______ type for case values.
- Which operator is used to compare if two values are equal in C++?
- While creating a networking application, you find a need to define a data type that can hold various data related to a network packet, such as its ID, source, destination, and payload. You also require a function to calculate the checksum of the packet. Which user-defined data type in C++ would be best suited for this use case?
- For a given function, once you start providing default values for arguments from the right, you cannot skip providing default values for subsequent arguments on the ______.
- What could be a reason for choosing pass by pointer over pass by reference in a function?