How does Java determine which overloaded method to call?
- Java calls the method randomly, as it cannot determine which one to call.
- Java calls the method that exactly matches the arguments provided during the method call.
- Java calls the method with the fewest number of parameters.
- Java calls the method with the most number of parameters.
Java determines which overloaded method to call by examining the number and types of arguments provided during the method call. It looks for the method that exactly matches the provided arguments. If no exact match is found, it results in a compilation error.
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