How is method overloading resolved when there is an ambiguity in method signatures?
- The JVM randomly selects one of the overloaded methods.
- The compiler throws an error and asks for explicit casting of parameters.
- The method with the least specific parameter types is chosen.
- The method with the most specific parameter types is chosen.
In Java, when there is an ambiguity in method signatures during method overloading, the compiler chooses the method with the most specific parameter types. Specificity is determined by the inheritance hierarchy, with the most specific type being favored. This ensures that the correct method is called based on the arguments provided.
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