Matrix exponentiation offers a method to compute Fibonacci numbers with _______ time complexity, making it highly efficient for large values of n.
- O(2^n)
- O(log n)
- O(n)
- O(n^2)
Matrix exponentiation provides a method to compute Fibonacci numbers with O(log n) time complexity. This efficient algorithm is especially advantageous for large values of n compared to the traditional recursive approach with higher time complexity.
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